A particle moving at nearly the speed of light (v c) passes through a region whe

Question

A particle moving at nearly the speed of light (v c) passes through a region where it is subjected to a magnetic force of constant magnitude that is always perpendicular to the momentum and has a magnitude of 3 × 10^10 N. As a result, the particle moves along a circular arc with a radius of 9 m. What is the magnitude of the momentum of this particle?

Since from p = mv here is undefined, and no mass is given, I am guessing that the momentum has something to do with perpendicular p/t, but I am in general at a loss as to how to approach this.

Explanation / Answer

magnetic force is the force that makes the particle to move in circular arc

so centripetal force = mv2/r = magnetic force

m = mass of particle = 3 x 10-10 x 9 / c2 = 3 x 10-26 kg

angular momentum = mvr = 3 x 10-26 x c x 9 = 3 x 10-26 x 3 x 108 x 9 = 8.1 x 10-17 kgrad/s

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