A sky diver of mass 80.0 kg (including parachute) jumps off a plane and begins h

Question

A sky diver of mass 80.0 kg (including parachute) jumps off a plane and begins her descent.
Throughout this problem use 9.80 m/s^2 for the magnitude of the acceleration due to gravity.

At some point during her free fall, the sky diver reaches her terminal speed. What is the magnitude of the drag force Fdrag due to air resistance that acts on the sky diver when she has reached terminal speed?

For an object falling through air at a high speed , the drag force acting on it due to air resistance can be expressed as

,F=Kv^2

where the coefficient K depends on the shape and size of the falling object and on the density of air. For a human body, the numerical value for K is about 0.250 kg/m.

Using this value for K, what is the terminal speed vterminal of the sky diver?

When the parachute is fully open, the effective drag coefficient of the sky diver plus parachute increases to 60.0 kg/m. What is the drag force Fdrag acting on the sky diver immediately after she has opened the parachute?

What is the terminal speed vterminal of the sky diver when the parachute is opened?

Explanation / Answer

A) Yes and her acceleration is directly downward

B) 784 N

C) 56.0 m/s

D) Yes and her acceleration is directly upward

E) 188160 N F) 3.62m/s

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