The weight of a ball rolling down an inclined plane can be broken into two vecto

Question

The weight of a ball rolling down an inclined plane can be broken into two vector components: one acting parallel to the plane, and the other acting perpendicular to the plane. At what angle of inclination of the plane are these two components equal? Answer in units of degree At what angle of inclination of the plane will the parallel component be equal to zero? Answer in units of degree At what angle of inclination of the plane will the parallel component be equal to the weight? Answer in units of degree

Explanation / Answer

At what angle of inclination of the plane are these two components equal? 45 deg At what angle of inclination of the plane will the parallel component be equal to zero? At zero degrees when the incline is not an incline, but flat At what angle of inclination of the plane will the parallel component be equal to the weight? At 90 degrees, when the incline is no longer an incline, but rather a wall. And the ball isn't rolling but rather falling.

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