On a vacation trip to St. Louis, MO from Fairmont a driver travels to Huntington

Question

On a vacation trip to St. Louis, MO from Fairmont a driver travels to Huntington, WV (190 miles) in 3 hours ; stops at a rest stop for 15 minutes; travels from Huntington to Lexington to St. Louis (385 miles in 6 hours)

A. What is the average speed for the trip from Fairmont to St. Louis?

B. What would have been the average speed if he had only taken 15 minutes for gas and food at Lexington?

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A runner changes his running speed from 7 m/s to 3/5 m/s in a time interval of 8 seconds. What is the average acceleration during this process?

Explanation / Answer

average speed=total d/time=190+385/9.25=62.16miles/hr average speed=190+385/9=63.88miles/hr accelaration=change in v/time=7-0.6/8=0.8m/s^2

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