P2------20cm-----Current1-----10cm-----Current 2-----10cm-----P1 The currents bo
ID: 1969201 • Letter: P
Question
P2------20cm-----Current1-----10cm-----Current 2-----10cm-----P1The currents both carry currents of 5.00 A but in opposite directions. The left one up and right one down. The currents are seperated by 10 cm. Find the magnitude and direction of the net magnetic field (A) at a point midway between the Wires. (B) at P1 , 10 cm to the right of the wire on the right, and (C) at P2, 20 cm to the left of the wire on the left
Current 1 is a verticle Wire with 5 A going up. Current 2 is a verticle wire with 5 A going down
Explanation / Answer
(A) Bnet=2*µ0*I/(2pr)=2*4p*10^-7*5/(2p*5*10^-2) =4*10^-5 T directed perpendicularly outwards to the plane containing the wires. (B) Bnet=µo*I/2pr1 - µo*I/2pr2 =µo*I/2p(1/r1- 1/r2)=4p*10^-7*5/2p (1/10 -1/20)*10^2 =5*10^-6 T directed perpendicularly outwards to the plane containing the wires. (C) Bnet=µo*I/2p(1/r1- 1/r2)= 4p*10^-7*5/2p *(1/20 -1/30)*10^2= 0.17*10^-5 T directed perpendicularly outwards to the plane containing the wires
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