A stream of water from a fire-fighter\'s hose hits a vertical wall. The firefigh

Question

A stream of water from a fire-fighter's hose hits a vertical wall. The firefighter knows that 16.9 kg of water are
emitted from the hose per second, and that the water has a speed of 45.5 m/s when it hits the wall. At the instant when it
hits the wall, the direction of the velocity vector of the water is 25.0 degrees BELOW the horizontal. Calculate the
average force exerted by the water on the wall, assuming that the vertical component of the velocity vector of the water is
unchanged but the horizontal component of the velocity vector is reversed when the water rebounds from the wall.

Explanation / Answer

average force=change in momentum per unit time =change vertical momentum + change horizontal momentum =0 + delta mv =16.9*(45.5 cos 25) =696.9 N

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