A material with an index of refraction of 1.37 is used to coat glass. The index

Question

A material with an index of refraction of 1.37 is used to coat glass. The index of refraction of glass is 1.5.
(a) What is the minimum thickness of the coating that will minimize the reflection of light with a wavelength of 5370 A? Answer in units of µm.
(b) Now assume that the coating’s index of refraction is 1.58. Assume that the rest of the system (from the previous question) remains the same.
What is the minimum thickness of the coating needed to minimize the reflection of this
light now? Answer in units of µm.

Explanation / Answer

air n=1 __________________ film n=1.37 __________________ glass n=1.5 thickness of film = wavelgth / 4n =5370/4 * 1.37 = 0.09799 micrometer b): air n=1 __________________ film n=1.58 __________________ glass n=1.5 2) thickness of film = 5370 /4n =0.08497 micrometer.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.