A material with an index of refraction of 1.37 is used to coat glass. The index

Question

A material with an index of refraction of 1.37 is used to coat glass. The index of refraction of glass is 1.5.

-What is the minimum thickness of the coating that will minimize the reflection of light with a wavelength of 6950 A?
Answer in units of m.

Now assume that the coating’s index of refraction is 1.56. Assume that the rest of the system (from the previous question) remains the same.

-What is the minimum thickness of the coat- ing needed to minimize the reflection of this light now?
Answer in units of m.

Explanation / Answer

air n=1 __________________ film n=1.37 __________________ glass n=1.5 thickness of film = wavelgth / 4n =6950/4 * 1.37 = 0.12625 micrometer air n=1 __________________ film n=1.56 __________________ glass n=1.5 2) thickness of film = 6950 /4n =0.111378 micrometer.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.