A material with an index of refraction of 1.33 is used to coat glass. The index

Question

A material with an index of refraction of 1.33 is used to coat glass. The index of refraction of glass is 1.5. What is the minimum thickness of the coating that will minimize the reflection of light with a wavelength of 5470 A? Answer in units of µm

Now assume that the coating’s index of refraction is 1.6. Assume that the rest of the system (from the previous question) remains the same. What is the minimum thickness of the coating needed to minimize the reflection of this light now? Answer in units of µm

Explanation / Answer

minimum thickness is t = lamda/(4*n) = (5470*10^-10)/(4*1.33)
=0.1028195*10^-6 m = 0.1028195 µm

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For n = 1.6
then t= (5470*10^-10)/(4*1.6) = 0.08546875*10^-6 m = 0.08546875 µm

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