A material with an index of refraction of 1.31 is used to coat glass. The index

Question

A material with an index of refraction of 1.31 is used to coat glass. The index of refraction of glass is 1.5. glass is 1.5. What is the minimum thickness of the coating that will minimize the re?ection of light with a wavelength of 4570 A? °
Answer in units of µm

Now assume that the coating’s index of refraction is 1.79. Assume that the rest of the
system (from the previous question) remains the same.
What is the minimum thickness of the coating needed to minimize the re?ection of this light now?
Answer in units of µm

Explanation / Answer

d = ?/4ncoating = 4570x10-10/4x1.31 = 0.0872 µm if ncoating = 1.79 d = 4570x10-10/2(1.79) = .12765 µm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.