Consider th epullly in figure 2 to be FRICTIONLESS. (picture is a pully system w

Question

Consider th epullly in figure 2 to be FRICTIONLESS. (picture is a pully system with two weights attached to eachother by a string laying horizontally across a table the one on farthest left (A) is 4 kg, then there's a string and the next weight (B) is 2 kg. The string then goes off the edge of the table to the right, connected to a pully and has a weight attached to it of 5kg (C).

What's the acceleration of block A?
What's the acceleration of block B?
What is the tention Fr in the rope (tention between blocks A and B)?

Explanation / Answer

as mass a is on table its gravity force is balanced by normal from table.

so the only force on system is F=mg=2*9.8=19.6N

so acceleration of system is a =F/m=19.6/(4+2) =3.267m/s^2

this is the acceleration of both mass .

so a of mass A =a of mass B = 3.267m/s^2

tension is the only force which is responsible for acceleration of mass A

so T= Ma = 4*3.267 =13.067 N

for more clear solution click on

http://www.flickr.com/photos/68952510@N04/6298008599/

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