Two Objects (m1 and m2) are connected by a string as show below. The object on t

Question

Two Objects (m1 and m2) are connected by a string as show below. The object on the tablehas a mass of 2.50 kg. There is a coefficient of friction between the object and the table of u=0.32. What does the mass of m2 need to be to make m1 move forward(to the right) with a constant acceleration to cover 2.0m in 1.6s starting from rest?

[m1]----------------> (To the left:m1 is on a table surface, as m2 is
| hanging off the edge, not on any surface.)
|
|
v
[m2]

Explanation / Answer

we know that s=0.5 *at^2 ==>a=1.5625m/sec^2 so net force on the system=(m+2.5)*1.5625 (m+2.5)*1.5625=mg-7.84(friction force) m*(9.8-1.5625)=11.74625 ==>m=1.42594841kgs

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