Two identical containers are open at the top and are connected at the bottom via

Question

Two identical containers are open at the top and are connected at the bottom via a tube of negligible volume and a valve that is closed. Both containers are filled initially to the same height of 1.00m, one with water (density: 1.00X10^3 kg/m^3) and the other with mercury (density: 13600 kg/m^3). The valve is then opened. Water and mercury are immiscible. Determine the fluid level in the left container when equilibrium is reestablished. (The left container contains water and mercury now).

How do I determine the new height of the left container?

(Where I am stuck: I believe that we use the pressure difference for a static fluid--since we are at equilibrium. This equation is P2 =P1 + (density)(accel due to gravity)(height). But there are two densities to deal with here. and P2 = P1 at the bottom of each container. From here, I do not know how to continue on.

Explanation / Answer

                                     H = 1.0 +0.463 = 1.463 m

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