Two wheels are free to spin about the same axle. The moment of inertia of wheel
ID: 1974743 • Letter: T
Question
Two wheels are free to spin about the same axle. The moment of inertia of wheel 1 is 2.44 kg m2, and the moment of inertia of wheel 2 is 1.46 kg m2. When the axle is in its initial position, wheel 1 spins clockwise with an angular speed of 35.00 rad/s, and wheel 2 spins counterclockwise with an angular speed of 37.80 rad/s.A) What is the magnitude of the angular momentum of the two disk system in this initial position? (in kg m2/s)
B) The axle is rotated, or tilted, by 180° to its final position. What is the magnitude of the vector quantity ?L? (in kg m2/s)
C)The wheels are returned to their initial position, and wheel 2 spins clockwise at 37.80 rad/s. What is the magnitude of the angular momentum of the two disk system in this new configuration? (in kg m2/s)
D) The axle is once again rotated, or tilted, by 180° to its final position. What is the magnitude of the vector quantity ?L? ( in kg m2/s)
Explanation / Answer
we take clockwise + ve then,
A) angular momentum(I) = 2.44 X 35 + 1.46 x (- 37.80) = 30.21 kg-m2
b) now direction of both angular velocties in opposite direction
L = 2.44 X (- 35) + 1.46 X 37.80 = -30.21 kg-m2
C) now both disk rotate clock wise so = + 37.80
L = 2.44 X 35 + 1.46 X 37.80 = 140.59 kg-m2
D) L = 2.44 X (- 35) + 1.46 X (-37.80) = - 140.59 m-s2
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