A block of mass m = 0.600 kg is fastened to an unstrained horizontal spring whos

Question

A block of mass m = 0.600 kg is fastened to an unstrained horizontal spring whose spring constant is k = 97.5 N/m. The block is given a displacement of +0.120 m, where the + sign indicates that the displacement is along the +x axis, and then released from rest.
(a) What is the force (magnitude and direction) that the spring exerts on the block just before the block is released?
-11.7 . N

(b) Find the angular frequency ? of the resulting oscillatory motion.
. rad/s

(c) What is the maximum speed of the block?
1.53 . m/s

(d) Determine the magnitude of the maximum acceleration of the block.
m/s2

Explanation / Answer

a) force = -97.5*.12 = -11.7N b)angular frequency = sqrt(k/m) = sqrt(97.5/.6) = 12.75 Hz c)maximum speed = sqrt(k/m)*x = 12.75*.12 = 1.53 m/s d)max acceleration = -11.7/.6 = -19.5 m/s2

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