A charged particle, moving horizontally with a speed V, is observed traveling in

Question

A charged particle, moving horizontally with a speed V, is observed traveling in a circular path in a uniform magnetic field. If a particle with the same mass and twice the charge entered the same magnetic field with twice the speed, the radius of the path would have been <<< unchanged >>>
why the answer is <unchanged>?? simple explain plz.



Consider two parallel current carrying wires in a horizontal plane. The current in the first wire is directed north and the current in the second wire is directed south. The force on the second wire due to the current in the first wire is ???
answer is <away from wire one> why is that?? explain plz.

Explanation / Answer

we have, Radius = r = mv/qB now, new radius r' = m(2v)/ ( 2q)B = mv/qB Radius remains the same !! 2. Use FLeming left hand rule. Please google it . you will find the answer !!

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