A charged particle is through a potential difference the particle them uniform m

Question

A charged particle is through a potential difference the particle them uniform magnetic field into while in this magnetic field the par tide travels in a semicircle of if we were to double the of the potential difference between a and b what would happen to the diameter d? Let the amount of time that the particle spends in the shaded region that field iff we were double the particle as it the field what would happen to t? t would double t would increase by a factor of Squareroot2 t would stay the same t would halve which is the sing of the charged particle? how are voltage v_a and v_b related?

Explanation / Answer

Part A)Using the formula

r = m x v/B x q

Since E/B = velocity and Eq = V

If the p.d is increased it doesn't affect the radius from the above equations

A)d would stay the same

Option C)

Part B) by the formula

T = 2 r/V

If V is doubled

Then T becomes half

So option E)

Part C)By the Fleming's hand rule

Force is acting perpendicular to the velocity and also charge travels from high potential to low potential

So option C)

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