A charged object is placed within an electric field of magnitude 1.2 × 104 N/C t

Question

A charged object is placed within an electric field of magnitude 1.2 × 104 N/C that points toward the left. If the object's charge is -2.4 C, what is the magnitude of the electric force that acts on the object?

Calculator Periodic Table Question 2 of 10 Map Sapling Learning this question was written by Steven Summers at Arkansas State University, Newport is placed within an electric field of magnitude 1.2 x101 N/C that points toward the left. If A charged the object's is-2.4 C, what is the magnitude of the electric force that acts on the object? 0 2.0 x 10-4 N O 2.9 x 104N 2.9 × 10-2 N O 5.0x102 N What direction is the electric force in? O to the left O down O to the right up Previous Check AnswerNext Exit

Explanation / Answer

1) Magnitude of electric field = qE

= 2.4*10^-6*1.2*10^4 =

= 0.0288 = 2.9*10^-2 N

Third option is the correct answer

2) since this is a negative charge the direction will be opposite to the direction of EF

so it will be to the right

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