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A charged object traveling 8m in a uniform electric field of 5 N/C experiences a

ID: 1427127 • Letter: A

Question

A charged object traveling 8m in a uniform electric field of 5 N/C experiences a 2J increase in kinetic energy. If the distance remains the same and the electric field is increased to 30 N/C, then what will be the new kinetic energy change of the charged object? A charged object traveling 8m in a uniform electric field of 5 N/C experiences a 2J increase in kinetic energy. If the distance remains the same and the electric field is increased to 30 N/C, then what will be the new kinetic energy change of the charged object?

Explanation / Answer

work = Force*displacement = change in KE

=> work = q*5*8 = 2

=> Work2 = q*30*8 = X

=> X = 12 J

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