Consider a particle moving in a straight line from initial point B to final poin

Question

Consider a particle moving in a straight line from initial point B to final point A, acted upon by a constant force F. (Part A figure) The force (think of it as a field, having a magnitude and direction at every position(r) ) is indicated by a series of identical vectors pointing to the left, parallel to the horizontal axis. The vectors are all identical only because the force is constant along the path. The magnitude of the force is F , and the displacement vector from point B to point A is L and L (of magnitude , making and angle (radians) with the positive x axis). Find , (W BA )the work that the force performs on the particle as it moves from point B to point A.find

Express the work in terms o f L , F, and radians. Remember to use radians, not degrees, for any angles that appear in your answer.find W BA?



Now consider the same force acting on a particle that travels from point A to point B. (Part B figure) The displacement vector now points in the opposite direction as it did in Part A. Find the work done by in this case.

Express your answer in terms of L, F, radians and .Find |w AB

Explanation / Answer

Please answer this physics question? Consider a particle moving in a straight line from initial point B to final point A, acted upon by a constant force F. (Part A figure) The force (think of it as a field, having a magnitude and direction at every position r ) is indicated by a series of identical vectors pointing to the left, parallel to the horizontal axis. The vectors are all identical only because the force is constant along the path. The magnitude of the force is F, and the displacement vector from point B to point A is L (of magnitude L, making and angle theta(radians) with the positive x axis). Find W(BA) , the work that the force F performs on the particle as it moves from point B to point A. Express the work in terms of L, F, and theta(angle). Remember to use radians, not degrees, for any angles that appear in your answer. the homework is online I put the answer: F*L and F*Lcos(theta) but computer says its wrong 3 years ago Report Abuse Additional Details part a figur is a bent vector to the left from point B to A with theta between them and the x-axis (this is the best I can do to describe its simply just a vector) the force vector is going to the left, and the length vector is going to the right. The answer should be F*L*cos(pi-theta). Find the work done by F_vec in this case? help thanks!? Not as long as it look...Help me with this please! thanks! Consider a particle moving in a straight line from initial point B to final point A, acted upon by a constant force F_vec. (Part A figure) The force (think of it as a field, having a magnitude and direction at every position r_vec) is indicated by a series of identical vectors pointing to the left, parallel to the horizontal axis. The vectors are all identical only because the force is constant along the path. The magnitude of the force is F, and the displacement vector from point B to point A is L_vec (of magnitude L, making and angle theta (radians) with the positive x axis). Find W_BA, the work that the force F_vec performs on the particle as it moves from point B to point A. a.) Consider the same force F_vec acting on a particle that travels from point A to point B. (Part B figure) The displacement vector L_vec now points in the opposite direction as it did in Part A. Find the work W_AB done by F_vec in this case. picture: http://i303.photobucket.com/albums/nn129/wvmounti31/MWE_wi_0_v1_a.jpg Work = Force x displacement W= Fdcos() plug in your #s the angle in part a) will be theta's supplement

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