Consider a particle of mass m = 17.0kg revolving around an axis with angular spe

Question

Consider a particle of mass m = 17.0kg revolving around an axis with angular speed . The perpendicular distance from the particle to the axis is r = 1.50m .<?xml:namespace prefix = o />

Assume = 29.0rad/s . What is the magnitude v of the velocity of the particle in m/s ?

Now that you have found the velocity of the particle, find its kinetic energy K .

Express your answer numerically, in joules.

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Consider a particle of mass m = 17.0kg revolving around an axis with angular speed The perpendicular distance from the particle to the axis is r = 1.50m . Assume = 29.0rad/s . What is the magnitude v of the velocity of the particle in m/s ? Now that you have found the velocity of the particle, find its kinetic energy K .

Explanation / Answer

v = radius*omega

=> v= 0.29*1.5 = 0.435 m/s

kinetic energy = 0.5mv^2 = 1.608 joules

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