After a long day of driving, John took a late-night swim in a hotel swimming poo

Question

After a long day of driving, John took a late-night swim in a hotel swimming pool. When he went back to his room after swimming, he realized that he had lost his room-key in the pool. He borrowed a powerful flashlight and walked to the edge of the pool, shining the light into it. The light shined on the key, which was lying on the bottom of the pool, when the flashlight was held 1.5 m above the water surface and was directed at the surface a horizontal distance of 1.2 m from the edge of the pool. If the water was 4 m deep, how far was the key from the edge of the pool?

(hint: read slowly and draw a neat picture. Although this seems a long problem, it is actually easy)

Explanation / Answer

the angle of incident. tan 0 = 1.5/1.2 so sin 0 =0.78. so angle of refraction. sin b = sin 0/1.333=0.59. so b=36 (degrees). so that the distance. 1.5+4*tan36=4.4(m

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