A bowling ball of mass M and radius R = 20.0 cm is released with an initial tran

Question

A bowling ball of mass M and radius R = 20.0 cm is released with an initial translational velocity of vi = 11.0  m/s to the right and an initial angular velocity of zero. The bowling ball can be treated as a uniform solid sphere. The coefficient of kinetic friction between the ball and the surface is 0.150 . The force of kinetic friction causes a linear acceleration, as well as a torque that causes the ball to spin. The ball rolls while slipping along the horizontal surface for some time, and then rolls without slipping at constant velocity after that. Use g = 10 m/s2.

a) What is the magnitude of the angular acceleration of the ball while it is sliding? 
 rad/s2

b) How far does the ball travel while it is sliding? 
 m

c) What is the constant speed of the ball when the ball rolls without slipping? 
 m/s

Explanation / Answer

FBD1 is correct
1)
T=I

=T/I=.15(M)g(.2)/[(2/5)M(.2)2]

=18.375 rad/s2

2)

x=112/(2*7.483)

x=8.085m

3)

11 m/s

hope that helps

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