during the first stage of its launch, a space shuttle goes from rest to 4973km/h

Question

during the first stage of its launch, a space shuttle goes from rest to 4973km/h while rising a vertical distace of 45 km. Assume constant acceleration and no variation in g over this distance. a)what is the acceleration of the shuttle? b) if a 55 kg astronaut is standing on a scale inside the shuttle during his launch, how hard will the scale push on her? start with a free body diagram of the astronaut. c)if this astronaut did not realize that the shuttle had left the launch pad, what would she think were her weight and mass?

i found question a, but i cannot find the rest, please help me

Explanation / Answer

change the value 4961 to 4973 for ur answer, hope this helps u Intial velocity of the space shuttle = U = 0 m/s final velocity of the shuttle = V= 4961 Km /h =4961x1000 /3600 m/s = 1378.06 m/s Vertical distance = S = 45km = 45000 m It is known by the formula for V2 - U2 = 2 aS thus, acceleration of the shuttle : a = V2/2S = (1378.06 )2/2 (45000) = 21.1 m/s2 Mass of the Astrounut = M = 55 kg How hard will the scale push on the astronaut : F = M (g + a) = M (9.8 + 21.1) = (55)(30.9) = 1699.5 N Note : If this astronaut did not realize that the shuttle had left the launch pad, what would she think were her weight and mass as She would think the scale reading is her weight, 539 N And she would therefore think her mass is 55.0kg

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