SHOW HOW YOU GET THE WORK Acceleration 1. The Bugatti Veyron can go from zero to
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Question
SHOW HOW YOU GET THE WORKAcceleration
1. The Bugatti Veyron can go from zero to 60 mph in 2.5 seconds.
(a) How many meters does it travel during the 2.5-s period?
(b) What is the Bugatti’s rate of acceleration?
2. A bullet traveling 220 m/s strikes a tree and penetrates 4.33 cm before stopping.
(a) Find the average acceleration of the bullet.
(b) Find the time it takes to stop.
3. Rocket-powered sleds are used to test the responses of humans to acceleration. Starting from rest, these sleds can reach a speed of 444 m/s in 1.8 seconds.
(a) Calculate the acceleration of these sleds.
(b) How far do these sleds travel during the 1.8-s of acceleration?
4. The highest speed ever achieved on a bicycle was 149.6 miles per hour. If this bicycle could slow down at a rate of -3 m/s2,
(a) how long would it take to stop?
(b) how many meters would it need to stop?
BONUS
A driver of car going 55 mph suddenly sees a deer 40 m in the road ahead. It takes him 0.75 s to apply the brakes. He slams on the brakes and starts to slow down at -10 m/s2.
? How far does he travel before deceleration?
? How long will it take him to stop?
? During deceleration, how far does the car go?
? Does the car hit the deer?
Explanation / Answer
Ans. 1: Using the first equation of motion, v = u + at and substituting u = 0, v = 60mph and t = 2.5s, we get a = (60 - 0) / 2.5 i.e. Acceleration, a = 24miles/s2.
Using the second equation of motion, s = ut + 0.5at2, we have that s = 0 + 0.5*24*2.52 i.e. Distance travelled s = 75 miles.
Ans. 2: v = 220m/s, u = 0, s = 4.33cm = 0.0433m.
(a) Using v2 = u2 + 2as, a = -558891.45m/s2 (retardation).
(b) Using v = u + at, t = 39.36ms.
Using the 3 equations of motion, the other questions can be solved in a similar manner.
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