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Question

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<p>A thermometer of mass 26.0g and specific heat 620 J/kg C&#176; is initially at a temperature of 11.0 &#176;C. If the thermometer is then immersed in a sample of water of mass 144g and the combination reaches a final temperature of 41.5 &#176;C, what was the initial temperature of the water?</p>
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Explanation / Answer

m1 = 26 g = 0.026 Kg S1 = 620 J/Kg K t1 = 11 degreeC m2 = 144 g = 0.144 Kg S2 = 4184 J/Kg K common temperature t = 41.5 degrees C initial temperature of water t2 = ? According to the law of calorimetry Heat lost by thermometer = Heat gained by water m1 S1 (t - t1) = m2 S2 (t2 - t) 491.66 = 602.49(t2 - 41.5) t2 - 41.5 = 0.816 t2 =42.31 degreesC

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