A violinist places her finger so that the vibrating section of a 1.1g/m string h
ID: 1990487 • Letter: A
Question
A violinist places her finger so that the vibrating section of a 1.1g/m string has a length of 30cm, then she draws her bow across it. A listener nearby in a 20 degree celcius room hears a note with a wavelength of 50cm.What is the tension in the string?I think what is getting me here is conversion facors. I'm not sure which all have to be converted, if any. I know cm need to be in m, but I don't know if g/m needs to be in kg/m for mass-density. I think you can solve the wavelength by using the velocity of sound and the frequency, and then, using that, solve tension using V=(sqrt) tention/massdensity, but I can't seem to get it to work. Thanks for any help you can offer.
Explanation / Answer
The equation for the fundamental frequency of an ideal taut string is:
f = (TL/m)/2L
also, f = v/ v=speed of sound in air at 20degrees C
so, v/ = (TL/m)/2L
so, (2Lv/)^2 = TL/m
so, T = (2Lv/)^2*m/L = (2*.3*343.2/.5)^2*1.1*10^-3= 186.6N
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