<p>Two positive charges, each one <span style=\"color: #dd0000;\">9</span> <span
ID: 1992295 • Letter: #
Question
<p>Two positive charges, each one <span>9</span> <span><em>μ</em></span>C lie on the x axis and form the base of an equilateral triangle with sides <span>20</span> cm. A negative charge of -<span>1</span> <span><em>μ</em></span>C is at the peak of the triangle.</p><div class="indent">(a) What is the x component of the electric field at a point P midway between the two positive charges (assume the positive x-direction is to the RIGHT)? <br /> N/C<br /><br />(b) What is the y component of the electric field at a point P midway between the two positive charges (assume positive y-direction is UP)? <br />N/C<br /><br />(c) If a negative charge of -<span>3</span> nC is placed at the point P, what is the x-component of the NET force on it? <br />N<br /><br />(d) If a negative charge of -<span>3</span> nC is placed at the point P, what is the y-component of the NET force on it? <br />N</div>
Explanation / Answer
a) x Component is zero since the EF due to the two 8 micro C cancles each other
b) y component is
E= kq/r^2 = 9 x 109 x 1 x 10-6/(1.7320 x 0.1)2 = 300 x 10^3 up direction
C) If a negative charge of -3 nC is placed at the point P
x component force is 0
d) y component force is F=Eq=300x10^3x3x10^-6 = 0.9 N negative y direction
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