During buildup in a series RC circuit. The voltage across the resistor equals th

Question

During buildup in a series RC circuit. The voltage across the resistor equals the voltage across the capacitor. The voltage across the capacitor equals the source voltage at all times. the voltage across the resistor and the voltage across the capacitor equals the the voltage across the resistor equals the source voltage at all times. For a series RC circuit, the time constant equals C/R l/(Rc) RC None of the above The direction of the current through an inductor in a series RL circuit during decay is meaningless; there is no current through an inductor during decay. the same as the direction during buildup. the opposite of the direction during buildup. None of the above For a series RL circuit the time constant equals R/L. LR 1/(RL) None of the above. The form of an exponential delay expression is A(1 - e^- t/tau) A e^+ t/tau. A e^- t/tau None of the above. At t greaterthanorequalto 5 tau during buildup, the current in a series RL circuit is equal to its DC steady-state value. zero. equal to the current at t = 0. None of the above. At t = 0, when a DC source is first switched on in a series RL circuit (the current is zero before switching), the voltage across the resistor is Zer. equal to the source voltage. equal to the DC steady-state value. None of the above

Explanation / Answer

Ans)

15. C

Reason : As per KVL(Kirchoff's voltage law ) the voltage of source in series RC circuit is equal to the sum of voltage across Resistor and voltage across capacitor

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16. C

For RC circuit time constant is t=RC

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17. B

The current direction during decay is same as that of build up ,as inductor current cannot change instantaneously and also current or energy stored in the same direction of build up ,so it decay in the same direction

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18.D

For series RL circuit time constant is t=L/R hence Ans =none of these as no answer available

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Only 1 question per post will be answered please ,but I answered 4 here

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