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(a) Just after the collision, what are the components of the center-of-mass velo

ID: 1997502 • Letter: #

Question

(a) Just after the collision, what are the components of the center-of-mass velocity of the satellite (vx and vy) and its rotational speed ?? (For vx, enter your answer to at least four significant figures.) vx t:

Your answer is correct. m/s vy = :

Your answer is correct. m/s ? = :

Your answer is incorrect. rad/s

(b) Calculate the rise in the internal energy of the satellite and space junk combined. Incorrect: Your answer is incorrect. J

ED webassign.net Homework20-F16 Chegg Study Guided Solutions and Study Help I Ch... Persuasive Presentation- Fall-2016-COM-11400-... Online calculator. Cross product of two vectors (v... 6. 2/4 points | Previous Answers M14 11.7.049 My Notes A spherical satellite of approximately uniform density with radius 6.3 m and mass 245 kg is originally moving with velocity 2600, 0, 0) m/s, and is originally rotating with an angular speed 2 rad/s, in the direction shown in the diagram. A small piece of space junk of mass 8.6 kg is initially moving toward the satellite with velocity (-2200, 0, o) m/s. The space junk hits the edge of the satellite as shown in the figure below, and moves off with a new velocity -1300, 480, 0) m/s. Both before and after the collision, the rotation of the space junk is negligible. M, R,I (a) Just after the collision, what are the components of the center-of-mass velocity of the satellite (vx and Vy) and its rotational speed ? (For vx, enter your answer to at least four significant figures.) Yv= 2568.40816 Vy 16.8489796 = 3.2536443 X rad/s m/s m/s (b) Calculate the rise in the internal energy of the satellite and space junk combined. Additional Materials Section 11.7 Submit Answer Save Progress

Explanation / Answer

Initial agular momentum = MR^2/2 *2-mv2 = 245*6.3^2/2*2 - 8.6*2200 = -9195

so final angular meomentum must alo be same so

MR^2/2*w -mvx = -9195

245*6.3^2/2*w-8.6*1300 = -9195

gives w = 0.408 rad/s (clockwise)

c) rise in energy = 0 since there is no other forces involved and so the energy always stays inthe system