Ampere\'s law HW-3 4. An Amperian shown at right near a wire with current lout o
ID: 1997928 • Letter: A
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Ampere's law HW-3 4. An Amperian shown at right near a wire with current lout of the page. oop is a. is line of the loop? Explain your reasoning magnetie field around the enrire closed Let Ls represent the integral of the magnetic field from point x to point Y along the straight left-hand segment of the loop, and let Le represent the line integral of the magnetic from point Y point xalong the curved segment of the loop. write an expression for Lc in terms of Ls. b. Suppose that the curved segment of the Amperian loop in part a is expanded as shown. The straight segment is unchanged. i. Does the value of Ls change? Explain your reasoning. ii. Does the value of Lechange? Explain your reasoning. c. the curved segment is made even larger so that it now x encloses the current-carrying wire, as shown. The straight segment is still unchanged. i. Does the value of Ls change? Explain your reasoning. ii. the value of Lc change? Explain your reasoning. Does Use Ampere's law to write an expression for Lein terms of Ls and L OTutorials in Introductory Physics, Physics Education Group, in of Washington (Autumn 2016)Explanation / Answer
4)
a) for the line integral , we will use the Aphere circuital law
line integral of magnetic field = u0 * Iin
Iin is the current flowing through the surface
as there is no current inside the loop
line integral of magnetic field = 0
Ls + Lc = 0
Ls = - Lc
b)
i) No , the value of Ls will not change as both XY and current wire is at the same place.
ii)No , as Lc = - Ls
and the value of Ls have not changed , the value of Lc will also not change.
c)
i)
the value of Ls will not change , both XY and current wire is at the same place.
ii) Yes ,value of Lc will change as
now , Ls + Lc = u0 * I
hence , value of Lc will change
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