9. Using the power law, P = I2R , calculate the resistance from current flow and

Question

9. Using the power law, P = I2R , calculate the resistance from current flow and power dissipation in Items 6 and 7. Use both the low and high values of I.

Item 6:

Item 7:

CAS-Astro-Lab X E Options h of physics Connect USB Device Send Ctrl-Alt-Delete E 160 mean free path (nm) 10 potential difference (-V) 100 nm show/hide trail total horizontal dist. of one carrier total charge (passing a point on wire) total energy (dissipated by ions) (average value) 2.0 20 5.0 4.0 3.0 1.0 10 2.0 1.0 10 10 10 time (ps) time (ps) time (ps) slope avg (drift) velocity 98.882 km/s slope avg. current 0.975 A slope avg. power 160.000 HW

Explanation / Answer

power = i^2R

R = power/i^2

For small current

R= 160e-6/0.975^2

= 1.683*10^-4 ohm

for large current, R = 160e-6/1.013^2

= 1.559*10^-4 ohm

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