Using the values from this experiment and Ohm’s Law (V=IR), calculate the resist
ID: 1998339 • Letter: U
Question
Using the values from this experiment and Ohm’s Law (V=IR), calculate the resistance of the circuit by using the amplitude of the current at resonance and where V is the amplitude of the applied voltage. Is this resistance equal to 10 W ? If not, what physical experimental uncertainties could have produced the discrepancy? Show your work.
Data
Frequency
VR
R
I
10
0.8994
10
0.08994
20
1.56
10
0.156
30
2.00
10
0.200
40
2.19
10
0.219
50
2.46
10
0.246
60
2.57
10
0.257
70
2.70
10
0.270
80
2.80
10
0.280
90
2.82
10
0.282
100
2.83
10
0.283
110
2.83
10
0.283
120
2.81
10
0.281
130
2.78
10
0.278
140
2.77
10
0.277
150
2.74
10
0.274
160
2.71
10
0.271
170
2.67
10
0.267
180
2.64
10
0.264
190
2.58
10
0.258
200
2.56
10
0.256
Frequency
VR
R
I
10
0.8994
10
0.08994
20
1.56
10
0.156
30
2.00
10
0.200
40
2.19
10
0.219
50
2.46
10
0.246
60
2.57
10
0.257
70
2.70
10
0.270
80
2.80
10
0.280
90
2.82
10
0.282
100
2.83
10
0.283
110
2.83
10
0.283
120
2.81
10
0.281
130
2.78
10
0.278
140
2.77
10
0.277
150
2.74
10
0.274
160
2.71
10
0.271
170
2.67
10
0.267
180
2.64
10
0.264
190
2.58
10
0.258
200
2.56
10
0.256
Explanation / Answer
Here resistance equal to 10 ohms as it is the intrinsic property of the material.
Thus the value depends on the given material and dimensions of the material.
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