Question 43 of 45 Incorrect Sapling Learning macmillan Consider the following nu

Question

Question 43 of 45 Incorrect Sapling Learning macmillan Consider the following nuclear fusion reaction: Each fusion event releases approximately 4.03 MeV of energy. How much total energy, in joules, would be released if all the deuterium atoms in a typical 0.270-kg glass of water were to undergo this fusion reaction? Assume that approximately 0.0115% of all the hydrogen atoms in the water are deuterium. Number A typical human body metabolizes energy from food at a rate of about 108.5 W, on average. How long, in days, would it take a human to metabolize the amount of energy calculated above? Number days A Previous Give Up & View Solution Check Answer Next Exit 8 Hint

Explanation / Answer

Here,

number of 2H atoms in 0.270 Kg water , N = (270/(18)) * 6.022 *10^23 * 2 * 0.0115 * 10^-2

N = 2.08 *10^21 atoms

Energy released by reaction , E = 2.08 *10^21/(2) * 4.03 *10^6 * 1.602 *10^-19

E = 6.714 *10^8 J

the energy released is 6.714 *10^8 J

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let the time taken is t

t * 108.5 = 6.714 *10^8

solving

t = 6.188 *10^8 s

t = 71.7 days

it can run the matabolism for 71.7 days

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