Find the magnitude of the electric field E_2 due to q_2 at P, as indicated in Fi

Question

Find the magnitude of the electric field E_2 due to q_2 at P, as indicated in Fig-1 0.28 N/C 0.72 N/C 7.20 N/C 0.28 V None Two parallel conducting wires each earn the same current of 4.5 mA. If the distance between them is 20 cm, what is the net magnetic field at point P, which is mid-way between the wires? 9.0 times 10^-10 T 0.0 T 4.5 times 10^-10 T 9.0 times 10^-12 T None What is the focal length of a lens that forms a virtual image 30.0 cm from the lens when the real image is placed 15 cm from the lens? 10.0 cm 15.0 cm 30.0 cm 45.0 cm None

Explanation / Answer

3) magnetic field due to top wire = uoI /2pi*r (in the page)

magnetic field due to bottom wire = uoI /2pi*r (out of the page)

since all the values are same and they are opposite in direction

net magnetic field will be zero

option B is the correct answer

4) using the lens equation we have

1/v + 1/u = 1/f

1/30 + 1/15 = 1/f

f = 10 cm

option A) is the correct answer

2) EF = kq2/r^2

= 9*10^9 *q2 / (3^2 + 4^2)

plug in the value of q2 anf solve the question

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