The capacitor in the figure below has a cross-sectional area A and a distance be

Question

The capacitor in the figure below has a cross-sectional area A and a distance between plates of 10 mm. A battery with voltage of 30 volts is connected across the plates of the capacitor There is nothing between the plates of the capacitor The dotted line AB is 1 mm from the top plate and the dotted line CD is 8 mm from the top plate. The lines are 10 mm lent and are centered on the plates. What is the potential at - B C If the voltage of the battery was doubled, what is the potential at - A D Please carefully explain your reasoning.

Explanation / Answer

we know that potenstial increases linearly from negative to positive plate, so

potential at B = 30-30*1/10 = 27 V

potential at C = 30 - 30*8/10 = 6V

Potenatial at A after doubling = 27*2 = 54V

potensial at D after doubling = 6*2 = 12V

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