A 35.0-kg child swings in a swing supported by two chains, each 3.06 m long. The

Question

A 35.0-kg child swings in a swing supported by two chains, each 3.06 m long. The tension in each chain at the lowest point is 438 N. (a) Find the child's speed at the lowest point

(b) Find the force exerted by the seat on the child at the lowest point. (Ignore the mass of the seat.) __________Nupward

Recently Bookmarked Recent laos Layer and (b) Compare this force with her welght by finding the ratio of the force to her welght. 1.93 Need Help? Talk to a Tutor points Previous Answer rs Ser P9 P022 MI HB My Notes Ask Your Teach A 35.0-kg child swings in a swing supported by two chains, each 3.06 m long. The tension in each chain at the lowest point is 438 N. (a) Find the child's speed at the lowest point. 6.67 Your incorrect answer may have result from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. m/s b) Find the force exerted by the seat on the child at the lowest nore the mass of the seat 852.2 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in Intermediate steps of your calculation. N (upward) Need Help? Master t Talk to a Tutor submit Answer Save Progress Practice Another verslon 33 points Previous Answer rs SenCP9 7. R023. My Notes Ask Your Teacher A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 33.0 m/s. With what maximum speed can it go around a curve having a radius of 86.5 m? m/s. 25.1 Need Help? Talk to a Tutor 12. 8/8 points I Previous Amswers 3erCP9 7.P035 My Notes Ask Your Teache Match Whale

Explanation / Answer

(A). Let us assume the motion at some point of time so foce balance on the child will be

2T = mg + mv2/r

where mv2/r is centrifugal force, T is the tension (since there is two chains, we multiply it by two)

Now plugging in what we have and solving for v, we get:

2 x (438) = (35) x (9.8) + (35) x (v2 / 3.06)

v = 6.826 m/s

(B) Child experiencing gravity mg and the normal force N exerted by the seat: we should have

N - mg = m(v2 / r)

N = mg +m(v2 / r) = 2T

N = 876 N

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