A 34cm diameter wheel accelerates uniformly about its center from 130rpm to 370r

Question

A 34cm diameter wheel accelerates uniformly about its center from 130rpm to 370rpm in 4.8s . A. Determine its angular acceleration in rad/s^2. B. Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.6s after it has started accelerating. (m/s^2) C. Determine the tangential component of the linear acceleration of a point on the edge of the wheel 1.6s after it has started accelerating. (m/s^2)

Explanation / Answer

w_o = 130 rpm = ((130*2*pi())/60) rad/s w = 370 rpm = ((370*2*pi())/60) rad/s t = 4.8 sec A)We know that w = w_o + alpha*t =>alpha = angular acceleration = (((370*2*pi())/60)-((130*2*pi())/60))/4.8 = 5.236 rad/s^2

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