Consider a capacitor with a capacitance of 10uF. You connect it to a variable DC

Question

Consider a capacitor with a capacitance of 10uF. You connect it to a variable DC voltage source with a switch in the circuit and a resistor of 1000 in series with the capacitor. A. What is the relation between the steady-state voltage across the capacitor and the charge? B. Before you close the switch, there is no charge on the capacitor. When you close the switch, current begins to flow from the voltage source at E volts. What is the relation between current and the voltage drop across the resistor in terms of the current and the resistance? C. What is the voltage drop across the capacitor in terms of charge and capacitance?

Explanation / Answer

Here ,

a) for the capacitor

steady state charge , Q = voltage * C

Q = 10 *10^-6 * V

B)for the voltage drop across the capacitor V

current is I

resistor = R

I = E/R

the current is E/R

C) for the voltage across the capacitor

V = Q/C

the voltage drop is Q/C

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