Calvin is on his sled again, sliding along a flat, icy surface at 4 m/s. Calvin

Question

Calvin is on his sled again, sliding along a flat, icy surface at 4 m/s. Calvin and the sled together have inertia of 25 kg. They crash into Hobbs this time (2 kg, in his winter boots). Hobbs was stationary before the crash, but falls onto the sled to join Calvin. Calvin & Hobbs & sled come to an icy uphill section, which is inclined at 10 degrees to the horizontal. How far do they slide uphill before coming to a brief halt? (After that they slide back down the hill.) Please give your answer to 2 significant figures in metres. (You will need g = 9.81 m/s^2 to get an answer to 2 s.f.) Your Answer:

Explanation / Answer

Total mass Calvin gathered here before crash is 25 kg and velocity of 4m/s

Hobb is at rest before crash having 2 kg

Using work Energy Theorem: 1/2 mv2 = Mghsin100

  1/2 * 25 * 16 = (25+2) * 9.8 *hsin100

  h = 4.35 m

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