Calculate the electric potential at the origin o due to the point charges in the

Question

Calculate the electric potential at the origin o due to the point charges in the figure below. at 4.5 X V GA +10 HC 20 HC x 2 cm. +5 cm +18 HC 15 HC GA O 2 cm. qD y: 3 cm. Four charges are placed in the xy-plane: charge A (qA 10 x 10 C) is located at x -2 x 10-2 m, y 0; change B (qB 20 x 10 6 C) is located at x 5 x 10 2 m, Y 0; charge C (qc 18 x 10 C) is located at x x 10 2 m, y 2 x 10 m; and charge D (qD 15 x 10 C) is located at x 0, y 3 x 10 m. The electric potential at the origin is equal to the sum of the potential due to each charge at that point.

Explanation / Answer

VA = K*qA/rA
=(9*10^9)*(10*10^-6) / (2*10^-2)
= 4.5*10^6 V

VB = K*qB/rB
=(9*10^9)*(-20*10^-6) / (5*10^-2)
= -3.6*10^6 V

rC = sqrt (2^2 + 2^2) = 2.83 cm = 2.83*10^-2 m
VC = K*qC/rC
=(9*10^9)*(18*10^-6) / (2.83*10^-2)
= 5.72*10^6 V

VD = K*qD/rD
=(9*10^9)*(-15*10^-6) / (3*10^-2)
= -4.5*10^6 V

V = VA + VB + VC + VD
= (4.5*10^6 ) + ( -3.6*10^6 ) + (5.72*10^6) + ( -4.5*10^6)
= 2.12*10^6 V
Answer: 2.12*10^6 V

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