In a population where the eye color gene can be determined by 4 alleles B(brown)

Question

In a population where the eye color gene can be determined by 4 alleles B(brown)=0.102631 , b(blue) =0.269870, h(hazel) =0.362110, g(green) =0.256310. The gene for eye shape can be determined by 3 alleles A (almond)=0.368990 m(monoloid)=0.356980 h(hooded)=0.236980. The gene for pupil size can be determined by 2 alleles I(large pupils)=0.489620 and i(small pupils)= 0.500120. Assume Hardy-Weinberg equlibrium, what is the frequency of getting Blue eyes, that are almond shaped with large pupils? (p2 + 2pq + q2 + 2pr + 2qr + r2 = 1) ?

Explanation / Answer

Solution :

let p = frequency of blue eye = 0.269870

let q = frequency of almond shape eye = 0.368990

let r = frequency of large pupil eye = 0.489620

now at Hardy-Weinberg equlibrium the values satisfy this equation => p2 + 2pq + q2 + 2pr + 2qr + r2 = 1

so for blue eye + almond shaped = 2pq

and for blue eye + large pupil = 2pr

therefore for blue eye + almond shaped + large pupil = 2pq + 2pr

                                                                                    =2*0.269870*0.368990 + 2*0.269870*0.489620

                                                                                    =0.463426162 (answer)

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