A mass attached to a spring is displaced from its equilibrium position by 5cm an

Question

A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?

A mass attached to a spring is displaced from its equilibrium position by  and released. The system then oscillates in simple harmonic motion with a period of . If that same mass–spring system is displaced from equilibrium by  instead, what will its period be in this case?

Explanation / Answer

time period remain same = 1 sec

because
T = 2 pi (m/k)^1/2

does not depend on displacement
depends on mass and spring constant which are same in both cases

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