A car travels along a straight line at a constant speed of 41.0 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 41.0 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 34.0 mi/h. What is the constant speed with which the car moved during the second distance d? Suppose the second distance d were traveled in the opposite direction; you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip? What is the average speed for this new trip?

Explanation / Answer

a)

34 = (41+v)/2

v = 68-41

v = 27 mi/hr

b)

average velocity remains Zero

c) average speed is same i.e. 41 mi/hr.

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