A car travels along a straight line at a constant speed of 40.5 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 40.5 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 27.0 mi/h. (a) What is the constant speed with which the car moved during the second distance d? . mi/h (b) Suppose the second distance d were traveled in the opposite direction; you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip? . mi/h (c) What is the average speed for this new trip?

Explanation / Answer

v=54-40.5=13.5mi/h v=40.5-13.5 /2=13.5mi/h v=13.5 mi/h

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