A car travels along a straight line at a constant speed of 40.5 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 40.5 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 29.5 mi/h. (a) What is the constant speed with which the car moved during the second distance d?(b) Suppose the second distance d were traveled in the opposite direction; you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip?(c) What is the average speed for this new trip?

Explanation / Answer

Avg speed = 2*v1*v2/(v1 + v2)
29.5= 2*40*v2/(40+v2)
1180 + 29.5*v2 = 80*v2
1180 = 50.5*v2

v2 = 23.367 mi/hr

(b) If the distance is the same, the direction is irrelevant.

(c) same as the above

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