Consider the following data from a hypothetical test-cross for linkage of an ima

Question

Consider the following data from a hypothetical test-cross for linkage of an imaginary laboratory insect. Assume Morgan's typical annotation, where a superscript + (+) = wild type phenotype, and lower-case letters indicate that the mutation is recessive.

Genes: b = black body mutation vg = vestigial wings mutation
P0 cross: (male parent) b vg+/b vg+ X  (female parent) b+ vg/b+ vg

F1 offspring: b vg+/b+vg
F1 testcross: b vg+/b+ vg X b vg/b vg (homozygous recessive individual)

F1 testcross sample results:

What is the map distance between these two genes?

What does this tell us about the linkage of the two genes?

offspring types number: b vg+/b vg 431 b+ vg+/b vg 0 b+ vg/b vg 569 b vg/b vg 0

Explanation / Answer

F1 testcross sample result shows a unequal distribution of gametes.As the recombination frequency is 0, no map distance between them. It means both genes are tightly associated and during meiosis seperation could not occur. Both alleles of the gene are attached toghther means they are linked and linkage is 100%.

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