(a) The square surface shown in the figure measures 4.4 mm on each side. It is i

Question

(a) The square surface shown in the figure measures 4.4 mm on each side. It is immersed in a uniform electric field with magnitude E = 1300 N/C. The field lines make an angle of = 35°with a normal to the surface, as shown. Take the normal to be directed "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.
= ______N·m2/C

(b) A point charge of 9.2 µC is at the center of a cubical Gaussian surface 58 cm on an edge. What is the net electric flux through the surface?
= _____N·m2/C

Explanation / Answer

a) = E Acos =180° 35°

= (1300N /C) (.0016m) cos(180° 35°)

= 1.70 N m^ 2 /C

Note that the angle is 180-35. This makes the flux negative--which means the flow is into the box. A net flow into a closed surface is taken to be negative

b) The flux = q enclosed/o

= 9.2x10^-6/8.854x10^-12 = 10.39x10^5 N-m^2/C

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