Side Side 2) The solutions in the arms of a U-Tube are separated at the bottom b

Question

Side Side 2) The solutions in the arms of a U-Tube are separated at the bottom by a selectively A Initial setup B 0.4M glucose 0.5M 0.8 M glucose permeable membrane. The 0.4M membrane is permeable to glucose but not to sodium Membrane chloride. Side A is filled with a solution of 0.4 molar glucose and 0.5 molar sodium chloride (NaCI), and Side B is filled with a solution containing 0.8 molar glucose and 0.4 molar sodium chloride. Initially, the volume in both arms is the same At the beginning of the experiment, which side is hypertonic and which side is hypotonic? If you examine side A after 3 days, what should have happened? (Describe whether the glucose, sodium chloride, and water stayed where they were, or moved to the right or left across the membrane)

Explanation / Answer

A hypotonic solution has less solute concentration than a hypertonic solution. At the beginning, A has .4 M glucose and .5 M NaCl. Total solute concentration in A is ( .4M + .5M) = .9 M

B has .8M glucose and .4 M NaCl. Solute concentration in B is ( .4M + .8M) = 1.2 M

Water level is same in both the tubes.

Hence, A is hypotonic to B.

B is hypertonic to A.

When NaCl is dissolved in water, it dissociates into Na+ and Cl- . The partial negative charge of oxygen of water will surround the positive charge of the Na+ ions and the partial positive charge of the hydrogen of water will surround the negative charge of Cl- ions. When all the ions of NaCl will be surrounded by water molecules, they will disperse in the solution. So, after 3 days the concentration of NaCl will decrease and water level will also decrease as water will pass through the membrane.

Glucose passage through artificial membrane is very slow. So, glucose concentration will remain almost same.

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