A 5.40kg box is sliding across the horizontal floor of an elevator. The coeffici

Question

A 5.40kg box is sliding across the horizontal floor of an elevator. The coefficient of kinetic friction between the box and the floor is 0.330. Determine the kinetic frictional force that acts on the box for each of the following cases:
a) the elevator is stationary
_____N
b) the elevator is accelerating upward with an acceleration whose magnitude is 1.30m/s^2
_____N
c) the elevator is accelerating downward with an acceleration whose magnitude is 1.30m/s^2
_____N

I need to be shown how to work this problem and be given the answers as well please

Explanation / Answer

Mass of the box, m = 5.40 kg Coefficient of kinetic friction, = 0.330 (a) Kinetic friction, f = N                           = m g                           = 0.330 * 5.40 * 9.80                           = 17.46 N (b) Kinetic friction, f = m ( g + a )                           = 0.330 * 5.40 * ( 9.8 + 1.3 )                           = 19.78 N (c) Kinetic friction, f = m ( g - a )                           = 0.330 * 5.40 * ( 9.8 - 1.3 )                           = 15.15 N Kinetic friction, f = m ( g - a )                           = 0.330 * 5.40 * ( 9.8 - 1.3 )                           = 15.15 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.